Indians acquire Jarrett Grube from Blue Jays

KANSAS CITY, MO. - JUN 02: A Cleveland Indians cap and glove as seen during a MLB game between the Cleveland Indians and the Kansas City Royals, June 02, 2017, at Kauffman Stadium, Kansas City, MO. The Royals won, 4-0. (Photo by Keith Gillett/Icon Sportswire)
Keith Gillett/Icon Sportswire

The Cleveland Indians have officially acquired right-handed pitcher Jarrett Grube from the Toronto Blue Jays, the clubs announced on Sunday afternoon. The Indians have elected to immediately assign Grube to Triple-A Columbus.

It is also worth noting that the seasoned right-hander will head to Cleveland in exchange only for cash considerations.

The 35-year-old Grube has just one big league appearance under his belt despite his age. With the lone outing coming back in 2014 as a member of the Los Angeles Angels, he amassed a mere two-thirds of an inning pitched while allowing one hit, one earned run and one home run. However, he did not register a walk, strikeout, win, loss, save, hold or blown save as a result of the appearance from three seasons ago.

Most recently, Grube made 11 starts for Triple-A Buffalo, the highest minor league affiliate of the Blue Jays. Over the course of 55.2 innings of work in 2017, he has produced a 6.14 ERA alongside a nearly even 2-3 record. While his opponents batted .286 against him during his time in upstate New York, Grube also accumulated 47 strikeouts against 21 walks for Triple-A Buffalo.

He was originally selected by the Colorado Rockies in the 10th round of the 2004 MLB Draft and has become quite the journeyman over the years. Although remaining at the Triple-A level since 2009, he has received just one opportunity to showcase his talents at the big league level as it stands today.

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